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٢٤٠",[288,291,294,297],{"_8":289,"_54":290},160241,"١٨٠",{"_8":292,"_54":293},160242,"٢٤٠",{"_8":295,"_54":296},160243,"٣٦٠",{"_8":298,"_54":299},160244,"٧٠٠",[],{"_147":302},[171,9,149],{"_8":304,"_52":53,"_54":305,"_12":306,"_10":307,"_60":61,"_129":-5,"_62":9,"_92":9,"_63":308,"_65":309,"_67":19,"_68":19,"_69":-5,"_70":310,"_100":319,"_102":41,"_144":41,"_145":320,"_75":322},40816,"إذا كان ٢٠ % من ربع ( س + ١ ) = ٢ ، قارن بين 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١٤",{"_8":324,"_52":53,"_54":325,"_12":326,"_10":327,"_60":128,"_129":-5,"_62":9,"_92":9,"_63":-5,"_65":-5,"_67":19,"_68":19,"_69":-5,"_70":328,"_100":341,"_102":41,"_144":41,"_145":342,"_75":345},40814,"ما مجموع أول ثلاث حدود في المتابعة التي حدها النوني \\rtl{أن={(\\frac{\\;۱\\;}{\\;۲\\;})}^ن\\;} ، ن > صفر","40814-%D9%85%D8%A7-%D9%85%D8%AC%D9%85%D9%88%D8%B9-%D8%A3%D9%88%D9%84-%D8%AB%D9%84%D8%A7%D8%AB-%D8%AD%D8%AF%D9%88%D8%AF-%D9%81%D9%8A-%D8%A7%D9%84%D9%85%D8%AA%D8%A7%D8%A8%D8%B9%D8%A9-%D8%A7%D9%84%D8%AA%D9%8A-%D8%AD%D8%AF%D9%87%D8%A7-%D8%A7%D9%84%D9%86%D9%88%D9%86%D9%8A-%7B%DB%B2%7D)%7D%5E%D9%86%7D-%D9%86-%3E-%D8%B5%D9%81%D8%B1-%7B%DB%B8%7D%7D-%7B%D9%A4%7D%7D-%7B%DB%B8%7D%7D-%7B%D9%A4","ما مجموع أول ثلاث حدود في المتابعة التي حدها النوني أن=( ۱ ۲ )/^ن ، ن > صفر أ- ۹ ٤ /ب- ۷ ۸ /ج- ۳ ٤ /د- % ٥ ۸",[329,332,335,338],{"_8":330,"_54":331},160217,"\\rtl{\\frac{\\;۳\\;}{\\;٤\\;}}",{"_8":333,"_54":334},160218,"\\rtl{\\frac{\\;۷\\;}{\\;۸\\;}}",{"_8":336,"_54":337},160219,"\\rtl{\\frac{\\;٥\\;}{\\;۸\\;}}",{"_8":339,"_54":340},160220,"\\rtl{\\frac{\\;۹\\;}{\\;٤\\;}}",[],{"_147":343},[171,9,194,344],947,"ما مجموع أول ثلاث حدود في المتابعة التي حدها النوني $\"\"/$ ، ن > صفر","detailedAnswer",[348,358,360,362],{"_8":73,"_54":74,"_349":19,"_350":351,"_357":-5},"is_correct","question_option_details",[352],{"_8":353,"_54":354,"_355":-5,"_356":-5},36552,"نفرض قيم موجبة أ = ١ و ب = ٢ لأن أ < ب ، ثم نعوض:\nالقيمة الأولى : \n\\rtl{{(\\;\\frac١٣\\;)}^{\\;\\;أ\\;\\;}^\\;\\;=\\;{(\\;\\frac١٣\\;)}^{\\;۱\\;}^\\;\\;=\\;\\frac١{\\;٣\\;}\\;}\nالقيمة الثانية : \n\\rtl{{(\\;\\frac١٣\\;)}^{\\;\\;ب\\;\\;}^\\;\\;=\\;{(\\;\\frac١٣\\;)}^{\\;۲\\;}^\\;\\;=\\;\\frac١{\\;\\;۹\\;\\;}}\nبالتالي \\rtl{{\\frac١{\\;\\;٣\\;\\;}\\;}\\;>\\;\\frac١{\\;\\;۹\\;\\;}}\n كذلك نفرض قيم سالبة أ= -٢ و ب= -١ ومن ثم نعوض:\n*عندما يكون الأس سالبًا، نأخذ مقلوب الكسر ونرفعه للأس.\nالقيمة الأولى : \n\\rtl{{(\\;\\frac١{\\;٣\\;}\\;)}^{\\;-۲\\;}^\\;=\\;{(\\;\\frac{\\;٣\\;}١\\;)}^{\\;۲\\;}\\;=\\;\\;٣^{\\;۲}\\;=\\;۹\\;\\;}\nالقيمة الثانية :\n\\rtl{{(\\;\\frac١{\\;٣\\;}\\;)}^{\\;-١\\;}^\\;=\\;{(\\;\\frac{\\;٣\\;}١\\;)}^{\\;١\\;}\\;=\\;\\;٣^{\\;١}\\;=\\;\\;\\;٣\\;\\;}\nبالتالي ٩ > ٣ \nإذن القيمة الأولى أكبر","entity_id","entity_user_id","has_access",{"_8":77,"_54":78,"_349":41,"_350":359,"_357":-5},[],{"_8":80,"_54":81,"_349":41,"_350":361,"_357":-5},[],{"_8":83,"_54":84,"_349":41,"_350":363,"_357":-5},[],"imagesURLs",[],"isMobile","questionId","streamId","routes/_visitor","actionData","errors"]