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بين:","40753-%D9%82%D8%A7%D8%B1%D9%86-%D8%A8%D9%8A%D9%86-%D8%A3%D8%B5%D8%BA%D8%B1-%D9%82%D9%8A%D9%85%D8%A9-%D9%84%D9%80%5E%7B%DB%B2%7D%7D-%D9%A2-%D8%A7%D9%84%D9%82%D9%8A%D9%85%D8%AA%D8%A7%D9%86-%D9%85%D8%AA%D8%B3%D8%A7%D9%88%D9%8A%D8%AA%D8%A7%D9%86-%D8%A7%D9%84%D9%85%D8%B9%D8%B7%D9%8A%D8%A7%D8%AA-%D8%BA%D9%8A%D8%B1-%D9%83%D8%A7%D9%81%D9%8A%D8%A9-%D8%A7%D9%84%D9%82%D9%8A%D9%85%D8%A9-%D8%A7%D9%84%D8%AB%D8%A7%D9%86%D9%8A%D8%A9-%D8%A3%D9%83%D8%A8%D8%B1-%D8%A7%D9%84%D9%82%D9%8A%D9%85%D8%A9-%D8%A7%D9%84%D8%A3%D9%88%D9%84%D9%89-%D8%A3%D9%83%D8%A8%D8%B1","قارن بين: أصغر قيمة لـ ( س+ ۱ )^ ۲ ٢ أ- القيمة الثانية أكبر ب- القيمة الأولى أكبر ج- المعطيات غير كافية د- القيمتان متساويتان","أصغر قيمة لـ\\rtl{\\;{(\\;س+\\;۱\\;)}^{\\;۲\\;\\;}}","٢",[334,336,338,340],{"_8":335,"_54":225},159973,{"_8":337,"_54":228},159974,{"_8":339,"_54":231},159975,{"_8":341,"_54":234},159976,[],{"_142":344},[123],"detailedAnswer",[347,352,359,361],{"_8":71,"_54":72,"_348":41,"_349":350,"_351":-5},"is_correct","question_option_details",[],"has_access",{"_8":76,"_54":77,"_348":19,"_349":353,"_351":-5},[354],{"_8":355,"_54":356,"_357":-5,"_358":-5},36541,"نبدأ بتبسيط الجزء الموجود تحت الجذر:\n\\rtl{\\;\\sqrt{\\frac{\\;\\;٦\\;\\;س^{\\;٤}\\;}{\\;۱۲\\;\\;}}\\;\\;\\\\\\;\\frac{\\;\\;٦\\;\\;س^{\\;٤}\\;}{\\;۱۲\\;\\;}\\;=\\;\\frac{\\;س^٤}۲\\;,\\;\\text{بالتالي يصبح:}\\;\\\\\\sqrt{\\frac{\\;\\;س^{\\;٤\\;}}۲}}\nإذن المعادلة تصبح:\n\\rtl{\\;س^{\\;۳\\;\\;}\\;=\\;\\sqrt{\\frac{\\;\\;س^{\\;٤\\;}}۲}}\n تبسيط الجذر , نعلم أن:\n\\rtl{\\;\\sqrt{\\frac{\\;\\;س^{\\;٤\\;}}۲}\\;\\;=\\;\\frac{\\sqrt{\\;س^{\\;٤\\;}\\;}}{\\sqrt{\\;\\;۲\\;\\;}}\\;\\;=\\;\\;\\frac{\\;\\;س^{\\;۲\\;\\;}}{\\sqrt{\\;\\;۲\\;\\;}\\;}}\nإذن المعادلة تصبح:\n\\rtl{\\;\\;س^{۳\\;}\\;=\\;\\;\\frac{\\;\\;س^{\\;۲\\;\\;}}{\\sqrt{\\;\\;۲\\;\\;}\\;}}\nنقسم كلا الطرفين على \\rtl{\\;س^{\\;۲\\;\\;}} :\n\\rtl{\\;\\;\\frac{\\;س^{۳\\;}}{\\;\\;س^{۲\\;\\;}}\\;=\\;\\frac{\\;\\frac{\\;\\;س^{\\;۲\\;\\;}}{\\sqrt{\\;\\;۲\\;\\;}\\;}}{\\;\\;س^{۲\\;\\;}}\\;\\;\\\\\\;س^{۳\\;-\\;۲}\\;\\;=\\;\\;\\frac{\\;\\;س^{\\;۲\\;\\;}}{\\sqrt{\\;\\;۲\\;\\;}\\;}\\;\\;\\times\\;\\;\\frac۱{\\;\\;س^{\\;۲\\;\\;}}\\;,\\;\\text{نلغي}\\;س^۲\\;\\text{من الطرفين:}}\n\\rtl{\\;\\;س^\\;\\;=\\;\\;\\frac{\\;\\;۱}{\\sqrt{\\;\\;۲\\;\\;}\\;}}\nللتخلص من الجذر في المقام، نضرب البسط والمقام بـ\\rtl{\\;\\sqrt{\\;\\;۲\\;\\;}}\n\\rtl{\\;\\;س^\\;\\;=\\;\\;\\frac{\\;\\;۱}{\\sqrt{\\;\\;۲\\;\\;}\\;}\\;\\;\\times\\;\\;\\frac{\\sqrt{\\;\\;۲\\;\\;}}{\\sqrt{\\;\\;۲\\;\\;}\\;}\\;\\;=\\;\\;\\frac{\\sqrt{\\;\\;۲\\;\\;}}{\\;۲}\\;}\nإذن قيمة س هي \\rtl{\\;\\frac{\\sqrt{\\;\\;۲\\;\\;}}{\\;۲}\\;}","entity_id","entity_user_id",{"_8":80,"_54":81,"_348":41,"_349":360,"_351":-5},[],{"_8":84,"_54":85,"_348":41,"_349":362,"_351":-5},[],"imagesURLs",[],"isMobile","questionId","streamId","routes/_visitor","actionData","errors"]

إذا كان، أوجد قيمة س

إذا كان $\rtl{\;س^{٣\;}=\;\;\sqrt{\frac{\;\;٦\;\;س^{\;٤}\;}{\;۱۲\;\;}}\;}$ ، أوجد قيمة س