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الأولى = أ × د وبتعويض القيم \nأ × د = أ × ( أ + ٣ )\n** القيمة الثانية ب × ج \nب × ج = ( أ + ١ ) × ( أ + ٢ ) \nثم نحسب القيمة لكل جزء بالمقارنة فيصبح لدينا \n**القيمة الأولى = \\rtl{\\;أ\\;\\times\\;(\\;أ\\;+\\;٣\\;)\\;\\;={\\;أ\\;}^{\\;٢\\;}\\;+\\;٣\\;أ\\:} \n** القيمة الثانية = \\rtl{\\;(\\;أ\\;+\\;١\\;)\\;\\times\\;(\\;أ\\;+\\;٢\\;)\\;\\;={\\;أ\\;}^{٢\\;}\\;+\\;٣\\;أ\\;+\\;٢\\;} \nوبمقارنة القيمتين فالقيمة الثانية أكبر","entity_id","entity_user_id",{"_8":80,"_54":81,"_348":41,"_349":360,"_351":-5},[],{"_8":83,"_54":84,"_348":41,"_349":362,"_351":-5},[],"imagesURLs",[],"isMobile","questionId","streamId","routes/_visitor","actionData","errors"]

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إذا كانت أ < ب < ج < د، وَ (أ)، (ب)، (ج)، (د) أعداد صحيحة متتالية
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